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Physics Question on mechanical properties of fluid

A soap film is formed on a rectangular frame of length 0.07m dipping in soap solution. The frame hangs from the arm of a balance. An extra weitht of 0.38×10−30.38 \times 10^{-3} kg is to be placed in opposite pan to balance the pull on the frame.The surface tension of the soap solution. (g=9.8m/s2)(g = 9.8 m/s^2)

A

0.027 Nm−10.027\,Nm^{-1}

B

0.072 Nm−10.072\,Nm^{-1}

C

0.27 Nm−10.27\,Nm^{-1}

D

27 Nm−127\,Nm^{-1}

Answer

0.027 Nm−10.027\,Nm^{-1}

Explanation

Solution

mg=TX2lmg = TX 2l