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Question: A soap bubble in vacuum has a radius of 3 cm and another soap bubble in vacuum has a radius of 4 cm....

A soap bubble in vacuum has a radius of 3 cm and another soap bubble in vacuum has a radius of 4 cm. If the two bubbles coalesce under isothermal condition, then the radius of the new bubble is

A

2.3 cm

B

4.5 cm

C

5 cm

D

7 cm

Answer

5 cm

Explanation

Solution

r=r12+r22=9+16=5 cmr = \sqrt { r _ { 1 } ^ { 2 } + r _ { 2 } ^ { 2 } } = \sqrt { 9 + 16 } = 5 \mathrm {~cm}