Question
Question: A smooth table is placed horizontally and an ideal spring of spring constant \(k = 1000\mspace{6mu} ...
A smooth table is placed horizontally and an ideal spring of spring constant k=10006muN/m and unextended length of 0.5m has one end fixed to its centre. The other end is attached to a mass of 5kg which is moving in a circle with constant speed 20m/s. Then the tension in the spring and the extension of this spring beyond its normal length are
A
5006muN,6mu0.56mum
B
6006muN,6mu0.66mum
C
7006muN,6mu0.76mum
D
8006muN,6mu0.86mum
Answer
5006muN,6mu0.56mum
Explanation
Solution
k=1000,m=5kg,l=0.5m,v=20m/s (given)
Restoring force = kx =rmv2=l+xmv2 ⇒ 1000x=0.5+x5(20)2 ⇒ x=0.5m
and Tension in the spring = kx =1000×21=500N