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Question: A smooth sphere of radius R and mass M is placed on the smooth horizontal floor. Another smooth part...

A smooth sphere of radius R and mass M is placed on the smooth horizontal floor. Another smooth particle of mass m is placed on the sphere and a horizontal force F is applied on the sphere as shown. If the particle does not slip on the sphere then the value of force F is –

A

F = mg cotq

B

F = Mg cotq

C

F=(m + M)g cotq

D

F =(m + M)g tanq

Answer

F=(m + M)g cotq

Explanation

Solution

By F.B.D of m

N sinq = mg and N cosq = ma

\ tanq = טמ Ž a = g cotq

\ F = (m + M)g cot q