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Question

Question: A smooth sphere of mass M moving with velocity u directly collides elastically with another sphere o...

A smooth sphere of mass M moving with velocity u directly collides elastically with another sphere of mass m at rest. After collision their final velocities are V and v respectively. The value of v is

A

2uMm\frac{2uM}{m}

B

2umM\frac{2um}{M}

C

2u1+mM\frac{2u}{1 + \frac{m}{M}}

D

2u1+Mm\frac{2u}{1 + \frac{M}{m}}

Answer

2u1+mM\frac{2u}{1 + \frac{m}{M}}

Explanation

Solution

Final velocity of the target

v2=(m2m1m1+m2)u2+2m1u1m1+m2v_{2} = \left( \frac{m_{2} - m_{1}}{m_{1} + m_{2}} \right)u_{2} + \frac{2m_{1}u_{1}}{m_{1} + m_{2}}

As initially target is at rest so by substituting u2=0u_{2} = 0 we get v2=2MuM+m=2u1+mMv_{2} = \frac{2Mu}{M + m} = \frac{2u}{1 + \frac{m}{M}}.