Solveeit Logo

Question

Question: A smallparticle of mass m moves in such a way that P.E. = –\(\frac{1}{2}\)mkr<sup>2</sup>, where k i...

A smallparticle of mass m moves in such a way that P.E. = –12\frac{1}{2}mkr2, where k is a constant and r is the distance of the particle from origin. Assuming Bohr's model of quantization of angular moment and circular orbit, r is directly proportional to –

A

n2

B

n

C

n\sqrt{n}

D

None of these

Answer

n\sqrt{n}

Explanation

Solution

12\frac{1}{2}× P.E. = K.E.

=12\frac{1}{2} [–12\frac{1}{2}mkr2] = 12\frac{1}{2}mv2, mvr = nh2π\frac{nh}{2\pi}

v2 = n2h24π2m2r2\frac{n^{2}h^{2}}{4\pi^{2}m^{2}r^{2}}; r4 = n2h22π2m2k2\frac{n^{2}h^{2}}{2\pi^{2}m^{2}k^{2}}