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Question: A small telescope has an objective lens of focal length 144 cm and an eye piece of focal length 6.0c...

A small telescope has an objective lens of focal length 144 cm and an eye piece of focal length 6.0cm. what is the separation between the objective and the eye piece?

A

0.75 m

B

1.38 m

C

1.0 m

D

1.5 m

Answer

1.5 m

Explanation

Solution

: The separation between the objective and the eye

Piece = Length of the telescope tube

f=f0+fef = f_{0} + f_{e}

Here,f0=144cm=1.44mf_{0} = 144cm = 1.44m

fe=6.0cm=0.06mf_{e} = 6.0cm = 0.06m

f=1.44+0.06=1.5m\therefore f = 1.44 + 0.06 = 1.5m