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Question

Physics Question on Properties of Solids

A small steel ball is dropped into a long cylinder containing glycerine. Which one of the following is the correct representation of the velocity time graph for the transit of the ball?

A

B

C

D

Answer

Explanation

Solution

The forces acting on the ball as it moves through glycerine include the gravitational force (mgmg) and the viscous drag force (FvF_v). The motion is described by:

mgFvFb=mamg - F_v - F_b = ma

Where:

Fb=(43πr3)g(ρL),Fv=6πηrvF_b = \left( \frac{4}{3} \pi r^3 \right) g (\rho_L), \quad F_v = 6 \pi \eta r v

Equating forces and simplifying:

(43πr3)g(ρρL)=mdvdt\left( \frac{4}{3} \pi r^3 \right) g (\rho - \rho_L) = m \frac{dv}{dt}

Let:

K1=43πr3(ρρL)g,K2=6πηrmK_1 = \frac{4}{3} \pi r^3 (\rho - \rho_L) g, \quad K_2 = \frac{6 \pi \eta r}{m}

The differential equation becomes:

dvdt=K1K2v\frac{dv}{dt} = K_1 - K_2 v

Integrating:

0vdvK1K2v=0tdt\int_0^v \frac{dv}{K_1 - K_2 v} = \int_0^t dt

Solution yields:

v=K1K2(1eK2t)v = \frac{K_1}{K_2} \left( 1 - e^{-K_2 t} \right)