Question

A small pack of cards consists of the Ace, king, queen, jack and ten of all four suits. Find the probability of selecting the queen of spades.

Answer 1

A standard deck of playing cards consists of $52$ cards all cards are divided into 4 units. There are two black suits, spades and clubs and two red suits of heart and diamond. In each suit there are 13 cards including $2,\,\,3,\,\,4,\,\,5,\,\,6,\,\,7,\,\,8,\,\,9,\,\,10$ a jack, a queen, a king and an ace.
Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur or how likely it is that a proposition is true. The probability of an event is a number between $0$ and $1$, where, roughly speaking, $0$ indicates impossibility of the event and $1$ indicates certainty.

Complete step by step solution:
Given no. of queen cards $= 4$
No. of jack cards $= 4$
And 10 of all four suits $= 10$
Now,
Total cards$= 4 + 4 + 4 + 4 + 40 = 52$ card
Selecting of queen of spades card $= 1$
Probability of queen card $= \dfrac{1}{{52}}$
So, the probability of selecting the queen of spades $= \dfrac{1}{{52}}$or $0.019$

Note: There is no other option. It is a direct question of the probability of the queen of spades.
Since I find the probability of not a queen of spades. Since probability that a first card is Not queen of spade is $\dfrac{{51}}{{52}}$
Probability of queen of spade is
$1 - \dfrac{{51}}{{52}} = \dfrac{1}{{52}}$