Question

A small mass executes S.H.M. account a point O with amplitude A & time period T. Its displacement from O at time T/8 after passing through O is -

• A. $\frac{A}{8}$
• B. $\frac{A}{2\sqrt{2}}$
• C. $\frac{A}{2}$
• D. $\frac{A}{\sqrt{2}}$

Answer 1

Answer: (D)

$\frac{A}{\sqrt{2}}$

Answer 2

Equation of S.H.M.

x = A sin ωt ; so when

t = T/8

x = A sin ω × T/8 = A

sin$\left\{ \frac{2\pi}{T} \times \frac{T}{8} \right\}$

= A sin $\frac{\pi}{4}$ = $\frac{A}{\sqrt{2}}$