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Question: A small lamp is hung at a height of 8 feet above the centre of a round table of diameter 16 feet. Th...

A small lamp is hung at a height of 8 feet above the centre of a round table of diameter 16 feet. The ratio of intensities of illumination at the centre and at points on the circumference of the table will be

A

1 : 1

B

2 : 1

C

22:12\sqrt{2}:1

D

3 : 2

Answer

22:12\sqrt{2}:1

Explanation

Solution

Illuminance at A, IA=Lh2I_{A} = \frac{L}{h^{2}}

Illuminance at B, IB=L(h2+r2)2cosθ=Lh(r2+h2)3/2I_{B} = \frac{L}{\sqrt{(h^{2} + r^{2})^{2}}}\cos\theta = \frac{Lh}{(r^{2} + h^{2})^{3/2}}

IAIB=(1+r2h2)3/2=(1+8282)3/2=23/2=22:1\therefore\frac{I_{A}}{I_{B}} = \left( 1 + \frac{r^{2}}{h^{2}} \right)^{3/2} = \left( 1 + \frac{8^{2}}{8^{2}} \right)^{3/2} = 2^{3/2} = 2\sqrt{2}:1