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Physics Question on Fluid Mechanics

A small hole of area of cross-section 2mm22 mm^2 is present near the bottom of a fully filled open tank of height 2m2 m. Taking g=10m/s2g=10 m/s2, the rate of flow of water through the open hole would be nearly:

A

12.6×10−6m3/s12.6 \times 10^{-6} m^3/s

B

8.9×10−6m3/s8.9 \times 10^{-6} m^3/s

C

2.23×10−6m3/s2.23\times 10^{-6} m^3/s

D

6.4×10−6m3/s6.4 \times 10^{-6} m^3/s

Answer

12.6×10−6m3/s12.6 \times 10^{-6} m^3/s

Explanation

Solution

The correct option is (A) :12.6×10−6m3/s12.6 \times 10^{-6} m^3/s