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Question

Physics Question on Inductance

A small coil is introduced between the poles of an electromagnet so that its axis coincides with the magnetic field direction. The number of turns is n and the cross-sectional area of the coil is AA. When the coil turns through 180180^{\circ} about its diameter, the charge flowing through the coil is QQ. The total resistance of the circuit is RR. What is the magnitude of the magnetic induction?

A

QRnA\frac{QR}{nA}

B

2QRnA\frac{2QR}{nA}

C

QR2RA\frac{QR}{2RA}

D

QR2nA\frac{QR}{2nA}

Answer

QR2nA\frac{QR}{2nA}

Explanation

Solution

Induced charge Q=nBAR(cosθ2cosθ1)Q=-\frac{n B A}{R}\left(\cos \theta_{2}-\cos \theta_{1}\right)
=nBAR(cos180cos0)=-\frac{n B A}{R}\left(\cos 180^{\circ}-\cos 0^{\circ}\right)
B=QR2nA\Rightarrow B=\frac{Q R}{2 n A}