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Physics Question on Electromagnetic induction

A small circular loop of area AA and resistance RR is fixed on a horizontal xyx y-plane with the center of the loop always on the axis n^\hat{n} of a long solenoid The solenoid has mm turns per unit length and carries current II counterclockwise as shown in the figure The magnetic field due to the solenoid is in n^\hat{ n } direction List-I gives time dependences of n^\hat{ n } in terms of a constant angular frequency ω\omega List-II gives the torques experienced by the circular loop at time t=π6ωt=\frac{\pi}{6 \omega}, Let α=A2μ02m2I2ω2R\alpha=\frac{A^2 \mu_0^2 m^2 I^2 \omega}{2 R}
A small circular loop of area

Column IColumn II
I12(sinωtj^+cosωtk^)\frac{1}{\sqrt{2}}(\sin \omega t \hat{j}+\cos \omega t \hat{k})
II12(sinωti^+cosωtj^)\frac{1}{\sqrt{2}}(\sin \omega t \hat{i}+\cos \omega t \hat{j})
III12(sinωti^+cosωtk^)\frac{1}{\sqrt{2}}(\sin \omega t \hat{i}+\cos \omega t \hat{k})
IV12(cosωti^+sinωtk^)\frac{1}{\sqrt{2}}(\cos \omega t \hat{i}+\sin \omega t \hat{k})
T

Which one of the following options is correct?

A

IQ,IIP,IIIS,IVTI \rightarrow Q , II \rightarrow P , III \rightarrow S , IV \rightarrow T

B

IS,IIT,IIIQ,IVPI \rightarrow S , II \rightarrow T, III \rightarrow Q, IV \rightarrow P

C

IQ,IIP,IIIS,IVRI \rightarrow Q , II \rightarrow P , III \rightarrow S , IV \rightarrow R

D

IT,IIQ,IIIP,IVRI \rightarrow T , II \rightarrow Q , III \rightarrow P , IV \rightarrow R

Answer

IQ,IIP,IIIS,IVRI \rightarrow Q , II \rightarrow P , III \rightarrow S , IV \rightarrow R

Explanation

Solution

IQ,IIP,IIIS,IVRI \rightarrow Q , II \rightarrow P , III \rightarrow S , IV \rightarrow R