Question

A small body of mass 0.10 kg is executing S.H.M. of amplitude 1.0 m and period 0.20 sec. The maximum force acting on it is

• A. 98.596 N
• B. 985.96 N
• C. 100.2 N
• D. 76.23 N

Answer 1

Answer: (A)

98.596 N

Answer 2

Maximum acceleration

$A_{\max} = a\omega^{2} = \frac{a \times 4\pi^{2}}{T^{2}} = \frac{1 \times 4 \times (3.14)^{2}}{0.2 \times 0.2}$

${F\frac{0.1 \times 4 \times (3.14)^{2}}{0.2 \times 0.2}\max}_{\max}$