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Question

Physics Question on distance and displacement

A small block slides down on a smooth inclined plane, starting from rest at time t=0. Let Sn be the distance traveled by the block in the interval t=n−1 to t=n. Then, the ratio SnS(n+1)\frac{S_n}{S_{(n+1)}}

A

2n2n−1\frac{2n}{2n-1}

B

2n−12n\frac{2n-1}{2n}

C

2n−12n+1\frac{2n-1}{2n+1}

D

2n+12n−1\frac{2n+1}{2n-1}

Answer

2n−12n+1\frac{2n-1}{2n+1}

Explanation

Solution

The correct answer is option (C): 2n−12n+1\frac{2n-1}{2n+1}