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Question

Physics Question on Friction

A small block of mass mm is kept on a rough inclined surface of inclination θ\theta fixed in a elevator. The elevator goes up with a uniform velocity vv and the block does not slide on the wedge. The work done by the force of friction on the block in time tt will be :

A

zero

B

mgvtcos2θmgvt \cos^2 \theta

C

mgvtsin2θmgvt \sin^2 \theta

D

mgvtsin2θmgvt \sin \, 2 \theta

Answer

mgvtsin2θmgvt \sin^2 \theta

Explanation

Solution

Wf=fsinθSW_{f}=f \sin \theta S =(mgsinθ)(sinθ)(vt)=(m g \sin \theta)(\sin \theta)(v t) =mgsin2θvt=m g \sin ^{2} \theta v t