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Question

Physics Question on Oscillations

A small block is connected to one end of a massless spring of unstretched length 4.9 m. The other end of the spring (see the figure) is fixed. The system lies on a horizontal frictionless surface. The block is stretched by 0.2 m and released from rest at t = 0. It then executes simple harmonic motion with angular frequency to = π3\frac{\pi }{3} rad/s. Simultaneously at t = 0, a small pebble is projected with speed v from point P at an angle of 45^{\circ} as shown in the figure. Point P is at a horizontal distance of 10 m from O. If the pebble hits the block at / = 1 s, the value of v is (takeg=10m/s2(take \, \, g = 10 m /s_2

A

50m/s\sqrt{50} m/s

B

51m/s\sqrt{51} m/s

C

52m/s\sqrt{52} m/s

D

53m/s\sqrt{53} m/s

Answer

50m/s\sqrt{50} m/s

Explanation

Solution

t = time of flight of projectile
=2vsinθg(θ=45)\, \, \, \, = \frac{ 2v sin \theta }{ g } \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, (\theta = 45 ^ \circ )
v=gt2sinθ=10×12×1/2\therefore \, \, \, \, v= \frac{ gt}{ 2 sin \theta = \frac{ 10 \times 1}{ 2 \times 1/ \sqrt 2}}
=50m/s\, \, \, \, \, \, \, \, \, \, = \sqrt {50} m/s