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Question: A small bar magnet of moment M is placed in a uniform field H. If magnet makes an angle of 30° with ...

A small bar magnet of moment M is placed in a uniform field H. If magnet makes an angle of 30° with field, the torque acting on the magnet is

A

MH

B

MH2\frac { M H } { 2 }

C

MH3\frac { M H } { 3 }

D

MH4\frac { M H } { 4 }

Answer

MH2\frac { M H } { 2 }

Explanation

Solution

τ=MHsin⁡θ=MHsin⁡30∘=MH2\tau = M H \sin \theta = M H \sin 30 ^ { \circ } = \frac { M H } { 2 }