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Question: A small ball is projected with initial speed u and at an angle q with horizontal from ground. The de...

A small ball is projected with initial speed u and at an angle q with horizontal from ground. The de-Broglie wavelength of ball at the moment its velocity vector becomes perpendicular to initial velocity vector is –

A

hmu\frac{h}{mu}

B

hmusin⁡θ\frac{h}{mu\sin\theta}

C

hmutan⁡θ\frac{h}{mu}\tan\theta

D

hmucos⁡θ\frac{h}{mu\cos\theta}

Answer

hmutan⁡θ\frac{h}{mu}\tan\theta

Explanation

Solution

At the moment its velocity vector is becomes perpendicular to initial velocity vector, its speed v = u cotq l = hmv\frac{h}{mv}