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Question

Physics Question on Wave optics

A slit of width a is illuminated by red light of wavelength 6500Ao6500\, \overset{\text{o}}{\mathop{\text{A}}}\, . If the first minimum falls at θ=30,\theta =30{}^\circ , the value of aa is

A

6.5×104mm6.5\times {{10}^{-4}}mm

B

1.3micron1.3\,\,micron

C

3250Ao3250\,\overset{\text{o}}{\mathop{\text{A}}}\,

D

2.6×104cm2.6\times {{10}^{-4}}cm

Answer

1.3micron1.3\,\,micron

Explanation

Solution

According to principle of diffraction
asinθ=nλa\sin \theta =n\lambda where n= n= order of secondary minimum \therefore
asin30=1×(6500×1010)a\sin 30{}^\circ =1\times (6500\times {{10}^{-10}})
or a=1.3×106ma=1.3\times {{10}^{-6}}m or a=1.3 microna=1.3\text{ }micron