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Question

Physics Question on Refraction of Light

A slit of width 'a' is illuminated by red light of wavelength 6500?6500 ?. If the first diffraction minimum falls at 30?30 ?, then the value of ' aa ' is

A

6.5×104mm6.5 \times 10^{-4} mm

B

1.31.3 micron

C

3250?3250 ?

D

2.6×104cm2.6 \times 10^{-4} cm

Answer

1.31.3 micron

Explanation

Solution

For diffraction minima
asinθ=nλa \sin \theta= n \lambda
n=1n =1 for I I minimum
a=λsinθ=6.5×107sin30a =\frac{\lambda}{\sin \theta}=\frac{6.5 \times 10^{-7}}{\sin 30}
=6.5×1070.5=\frac{6.5 \times 10^{-7}}{0.5}
=13×107=13 \times 10^{-7}
=1.3×106m=1.3 \times 10^{-6} m
=1.3=1.3 micron