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Question: A slit of size 0.15 cm is placed at 2.1 m from a screen. On illuminated it by a light of wavelength ...

A slit of size 0.15 cm is placed at 2.1 m from a screen. On illuminated it by a light of wavelength 5 × 10–5 cm. The width of central maxima will be.

A

70 mm

B

0.14 mm

C

1.4 mm

D

0.14 cm

Answer

1.4 mm

Explanation

Solution

Width of central maxima =2λDd= \frac{2\lambda D}{d}

=2×2.1×5×10−70.15×10−2=1.4×10−3m=1.4 6mumm= \frac{2 \times 2.1 \times 5 \times 10^{- 7}}{0.15 \times 10^{- 2}} = 1.4 \times 10^{- 3}m = 1.4\mspace{6mu} mm