Question

A slab of copper of thickness 'b' is inserted in between the plates of parallel plate capacitor. The separation of the plates is d. If b = $\frac { \mathrm { d } } { 2 }$ , then the ratio of the capacities of capacitor after and before inserting the slab is-

• A. $\sqrt { 2 }$ : 1
• B. 2 : 1
• C. 1 : 1
• D. 2 :

Answer 1

Answer: (B)

2 : 1

Answer 2

C_{partial medium} = $\frac { \epsilon _ { 0 } \mathrm {~A} } { ( \mathrm {~d} - \mathrm { t } ) + \frac { \mathrm { t } } { \epsilon _ { \mathrm { r } } } }$