Question

A slab consists of two plates of different materials of same thickness and having thermal conductivities $K_1$ and $K_2$. The equivalent thermal conductivity of the slab is

• A. $K_1 + K_2$
• B. $\frac{K_1 K_2}{K_1 + K_2}$
• C. $\frac{2 K_1 K_2}{K_1 + K_2}$
• D. $\sqrt{K_1 + K_2}$

Answer 1

Answer: (C)

$\frac{2 K_1 K_2}{K_1 + K_2}$

Answer 2

Answer (c) $\frac{2 K_1 K_2}{K_1 + K_2}$