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Question: A skier starts at the top of a snow ball with negligible speed and skis straight down the side. At w...

A skier starts at the top of a snow ball with negligible speed and skis straight down the side. At what point does he lose contact with the snowball.

A

θ = sin-123\frac { 2 } { 3 }

B

θ = cos-123\frac { 2 } { 3 }

C

θ = tan-123\frac { 2 } { 3 }

D

None of these

Answer

θ = cos-123\frac { 2 } { 3 }

Explanation

Solution

= mgh = mgR(1 – cos θ)

or = 2mg (1 – cos θ)

Condition of losing contact mv2R\frac { \mathrm { mv } ^ { 2 } } { \mathrm { R } } = mg cos θ

or 2mg(1 – cos θ) = mg cos θ or θ = cos-123\frac { 2 } { 3 }