Question

A siren providing a sound of frequency $800Hz$ which is moving away from an observer towards a cliff at a velocity of$15m{{s}^{-1}}$. Then, the frequency of sound the observer will listen in the echo reflected from the cliff is: Take velocity of sound in air =$330m{{s}^{-1}}$
$\begin{aligned} & A.765Hz \\\ & B.800Hz \\\ & C.838Hz \\\ & D.885Hz \\\ \end{aligned}$

Answer 1

Doppler Effect is the phenomena taking place in this question. The Doppler Effect is the phenomena in which variation in the frequency of a wave is taking place which is related to an observer who is in motion relative to the wave source. Here the observer is at rest. Therefore the velocity of the observer will be zero.

Complete step by step solution:

The general formula to find the apparent frequency is,
${{f}_{1}}=\dfrac{v\pm {{u}_{0}}}{v\mp {{u}_{s}}}f$
Where${{f}_{1}}$the frequency observer hears,$v$ is the velocity of sound in air,${{u}_{0}}$is the velocity of observer and ${{u}_{s}}$is the velocity with which siren is moving.
As observer is in rest,
${{u}_{0}}=0$
Now substituting the values of the variables mentioned in the question,

& {{u}_{s}}=15m{{s}^{-1}} \\\ & v=330m{{s}^{-1}} \\\ & f=800Hz \\\ \end{aligned}$$ Substituting this, $${{f}_{1}}=\dfrac{330\pm 0}{330\mp 15}800$$ As the source is moving towards the cliff, the source is moving towards the observer in effect. Therefore we can write that, ${{f}_{1}}=\dfrac{v}{v-{{u}_{s}}}f$ Substituting the values in this equation, $\begin{aligned} & {{f}_{1}}=\dfrac{330}{330-15}800 \\\ & {{f}_{1}}=838Hz \\\ \end{aligned}$ **Hence the correct answer is C.** **Note:** The waves emitted by an object which is traveling towards an observer will get compressed, providing a higher frequency as the source is approaching the observer. Doppler Effect is helpful in measuring the speed at which stars and galaxies are approaching or receding from the earth. This mechanism is referred to as a redshift or blueshift. Redshift occurs when light is coming from an object that is moving away is proportional to the wavelength hence shifted to the red end of the spectrum. Blueshift is the opposite to this.