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Question

Physics Question on sound

A siren emitting sound of frequency 500 Hz is going away from a stationary listener with a speed of 50m/s50\,\,m/s , the frequency of sound to be heard directly from the siren is:

A

286.5Hz286.5\,\,Hz

B

481Hz481\,\,Hz

C

434.2Hz434.2\,\,Hz

D

580Hz580\,\,Hz

Answer

434.2Hz434.2\,\,Hz

Explanation

Solution

Here: frequency of siren =500Hz=500\,\,Hz The speed of siren vs=50m/s{{v}_{s}}=50\,\,m/s Using Dopplers principle n=vv+vsnn'=\frac{v}{v+{{v}_{s}}}n or n=(330330+50)×500n'=\left( \frac{330}{330+50} \right)\times 500 or n=330×500380=434.2Hzn=\frac{330\times 500}{380}=434.2\,\,Hz