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Question

Physics Question on LCR Circuit

A sinusoidal voltage of peak value 300 V and an angular frequency ω\omega = 400 rad/s is applied to series L-C-R circuit, in which R = 3 Ω\Omega L = 20 mH and C = 625 μF.\mu F. The peak current in the circuit is

A

30 2\sqrt{2} A

B

60 A

C

100 A

D

60 2\sqrt{2} A

Answer

60 A

Explanation

Solution

The impedance of the circuit is Z=R2+(ZLXC)2Z=\sqrt{{{R}^{2}}+{{({{Z}_{L}}-{{X}_{C}})}^{2}}} XL=ωL=400×20×103=8H{{X}_{L}}=\omega L=400\times 20\times {{10}^{-3}}=8H XC=1ωC=1400×625×106=4C{{X}_{C}}=\frac{1}{\omega C}=\frac{1}{400\times 625\times {{10}^{-6}}}=4C Z=(3)2+(84)2=5Z=\sqrt{{{(3)}^{2}}+{{(8-4)}^{2}}}=5 i=EZ=3005=60Ai=\frac{E}{Z}=\frac{300}{5}=60A