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Question: A single slit of width 0.20 mm is illuminated with light of wavelength 500 nm. The observing screen ...

A single slit of width 0.20 mm is illuminated with light of wavelength 500 nm. The observing screen is placed 80 cm from the slit. The width of the central bright fringe will be.

A

1 mm

B

2 mm

C

4 mm

D

5 mm

Answer

4 mm

Explanation

Solution

Width of central bright fringe.

=2λDd=2×500×10−9×80×10−20.20×10−3=4×10−3m=4mm.= \frac{2\lambda D}{d} = \frac{2 \times 500 \times 10^{- 9} \times 80 \times 10^{- 2}}{0.20 \times 10^{- 3}} = 4 \times 10^{- 3}m = 4mm.