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Question: A simple spring has length \(l\) and force constant \(k\). It is cut into two springs of length \({l...

A simple spring has length ll and force constant kk. It is cut into two springs of length l1{l_1} and l2{l_2} such that l1=nl2{l_1} = n{l_2}( n is an integer) the force constant of a spring of length l1{l_1} is
A. k(1+n)k(1 + n)
B. nkn+1\dfrac{{nk}}{{n + 1}}
C. (1+n)kn\dfrac{{\left( {1 + n} \right)k}}{n}
D. kk

Explanation

Solution

We know that the length of the spring and force constant are inversely related. Total length ll of the spring is given as a sum of lengths l1{l_1} and l2{l_2}. By substituting for each length in terms of respective force constants and on solving we can find the value of the spring constant of length l1{l_1} in terms of the total spring constant kk.

Complete step by step answer:
It is given that a spring has a length of ll .
The force constant of the spring is kk.
Then the spring is cut into two springs of length l1{l_1} and l2{l_2} .
Relationship between l1{l_1} and l2{l_2} is given as
l1=nl2{l_1} = n{l_2}
Where, n is an integer.
We need to find the force constant of the spring of length l1{l_1} .
We know that the length of a spring and force constant are inversely related.
So, we can write it as
l1kl \propto \dfrac{1}{k}
l=ck\Rightarrow l = \dfrac{c}{k} (1)
Where, c is a constant of proportionality.
Let k1{k_1} be the force constant of spring with length l1{l_1} and k2{k_2} be the force constant of spring with length l2{l_2}.
Then we can write
l1=ck1\Rightarrow {l_1} = \dfrac{c}{{{k_1}}} (2)
And
l2=ck2\Rightarrow {l_2} = \dfrac{c}{{{k_2}}} (3)
We know that the total length ll is the sum of l1{l_1} and l2{l_2} .
l=l1+l2\Rightarrow l = {l_1} + {l_2}
l=l1+l1n\Rightarrow l = {l_1} + \dfrac{{{l_1}}}{n}
l1=nl2\because {l_1} = n{l_2}
Substituting the value of ll and l1{l_1}from equation 1 and 2, we get
ck=ck1+cnk1\Rightarrow \dfrac{c}{k} = \dfrac{c}{{{k_1}}} + \dfrac{c}{{n{k_1}}}
Now let us solve for k1{k_1} .
1k=1k1+1nk1\Rightarrow \dfrac{1}{k} = \dfrac{1}{{{k_1}}} + \dfrac{1}{{n{k_1}}}
1k=n+1nk1\Rightarrow \dfrac{1}{k} = \dfrac{{n + 1}}{{n{k_1}}}
k1=n+1nk\Rightarrow {k_1} = \dfrac{{n + 1}}{n}k
This is the value of the spring constant of length l1{l_1} .
Hence, the correct answer is option C.

Note: Remember that the length and spring constant are inversely related. If we increase the length of the spring then the force constant will decrease and if you decrease the length of spring then the force constant will increase. So, if we cut a spring in half the spring constant of each half will be doubled. In our case since l1=nl2{l_1} = n{l_2} The relation between spring constants of these parts will then be k2=nk1{k_2} = n{k_1}