Question

A simple pendulum with angular frequency ω oscillates simple harmonically. The tension in the string at lowest point is T. The total acceleration of the bob at its lowest position is –

• A. $\frac{T}{m}$ – g
• B. Zero
• C. g – $\frac{T}{m}$
• D. $\frac{T}{m}$ + g

Answer 1

Answer: (A)

$\frac{T}{m}$ – g

Answer 2

T – mg = mω²R

$\frac{T}{m}$ – g = ω²R = a