Question

A simple pendulum of frequency n falls freely under gravity from certain height from the ground level. Its frequency of oscillation will

• A. remain unchanged
• B. be greater than n
• C. be less than n
• D. become zero

Answer 1

Answer: (D)

become zero

Answer 2

For freely falling case the effective g is zero, so that frequency
of oscillation will be zero
As $\, \, \, \, \, f=\frac{2}{2 \pi} \sqrt{\frac{g_{eff}}{\lambda}}$
$\, \, \, \, \, \, \, \, \, \, f=\frac{1}{2\pi} \sqrt{\frac{0}{\lambda}}$
$\, \, \, \, \, \, \, \, \, \, \, \, \, f=0$