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Question: A simple pendulum makes 15 oscillations in 30 seconds. What is the time period and frequency of its ...

A simple pendulum makes 15 oscillations in 30 seconds. What is the time period and frequency of its oscillation?

A. 2 sec, 2 Hz

B. 2 sec, 1 Hz

C. 2 sec, 0.5 Hz

D. 2 sec, 4 Hz

Explanation

Solution

Time period is the total time taken by the body to complete 1 oscillation about its mean position. While frequency is defined as the number of oscillations made by the body about its mean position in 1 sec.

T=1fT = \dfrac{1}{f}

Complete answer:

Time period is the total time taken by the body to complete 1 oscillation about its mean position. While frequency is defined as the number of oscillations made by the body about its mean position in 1 sec. There is a mutual connection between time period and frequency which is given as:

T=1fT = \dfrac{1}{f}

According to the question the body makes 15 oscillations in 30 seconds so going by the definition of time period, the time taken to complete 1 oscillation is

T=3015sec=2secT = \dfrac{{30}}{{15}}\sec = 2\sec

And going by the definition of frequency, one oscillation is completed in

f=1530Hz=0.5Hzf = \dfrac{{15}}{{30}}Hz = 0.5Hz

This can also be done by the formula connecting the two parameters

\therefore f = 0.5\,Hz $$ Hence, the time period is 2 seconds and the frequency is 0.5 Hertz. **Therefore, the correct answer is option C.** **Note:** There is a saying ‘Work Smart not hard’. So, looking at the options given in the question, we note that the time period is the same in all options i.e. 2 sec. Using only the relation T=1/f, we would have got our answer. Apply this method in other similar questions to save time and energy especially in competitive exams.