Question

A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration a, then the time period is given by $T = 2\pi\sqrt{\frac{l}{g^{'}}}$, where $g^{'}$ is equal to

• A. g
• B. $g - a$
• C. $g + a$
• D. $\sqrt{g^{2} + a^{2}}$

Answer 1

Answer: (D)

$\sqrt{g^{2} + a^{2}}$

Answer 2

$g^{'} = \sqrt{g^{2} + a^{2}}$