A simple pendulum executing S.H.M. is falling freely along w... | PHYSICS - VELOCITY AND ACCELERATION IN SIMPLE HARMONIC MOTION | SolveeIt | Solveeit

Today, August 19

Question

A simple pendulum executing S.H.M. is falling freely along with the support. Then

A

Its periodic time decreases

B

Its periodic time increases

C

It does not oscillate at all

D

None of these

Answer

It does not oscillate at all

Explanation

Solution

$= \frac{2}{3}l$ ; for freely falling system effective $g = 0$ so $T = \infty$ or n = 0

It means that pendulum does not oscillate at all.