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Question

Question: A simple pendulum 4 m long swings with an amplitude of 0.2 m. What is its acceleration at the ends o...

A simple pendulum 4 m long swings with an amplitude of 0.2 m. What is its acceleration at the ends of its path ? (g = 10 m/s2)

A

Zero

B

10 m/s2

C

0.5 m/s2

D

2.5 m/s2

Answer

0.5 m/s2

Explanation

Solution

ω = gL\sqrt{\frac{g}{L}} ∴ amax = ω2A = gL\frac{g}{L} × A = 0.5 m/s2