Question
Question: A simple harmonic progressive wave of friction \(5Hz\) is traveling along the positive direction wit...
A simple harmonic progressive wave of friction 5Hz is traveling along the positive direction with a velocity of40ms−1. Calculate the phase difference between two points separated by a 0.8m distance.
Solution
Hint : Phase Difference is used to explain the difference in degrees or radians when two or more alternating quantities reach their maximum or minimum values. In this question equation containing wavelength, frequency and velocity is being used. By that way we can find the path difference and then its phase difference. If the path difference is λ, then the phase difference will be given as 2π.
Complete step by step solution: first of all let us discuss the path difference and phase difference. Path difference abbreviated as PD is the difference in the distance traversed by the two waves from their own sources in order to give a point a pattern. The path difference is equal to one wavelength. Phase Difference is used to explain the difference in degrees or radians when two or more alternating quantities reach their maximum or minimum values. The phase difference can be measured in degree or radian while path difference is measured in angstrom. If the path difference isλ, then the phase difference will be given as 2π .
In this question it is given that,
f=5Hzv=40ms−1
As we all know,
λ=fv
Substituting the values in it,
λ=540=8m
As we know the path difference is given by the formula,
Δϕ=Δλ2π
Substituting the value of path difference given in the question here in the Δϕ=5πrad is will give,
0.8=Δϕ2π
Therefore
Δϕ=5πrad
So the phase difference will be
Δϕ=5πrad
Hence we got the answer.
Note: simple harmonic motion is a special case in periodic motion in which the restoring force of the object in motion is directly proportional to the displacement of the object, magnitude and its act towards the equilibrium position of the object.