Question

A simple harmonic oscillator has an amplitude A and time period T. The time required by it to travel from $x = A$ to $x = A/2$ is

• A. $T/6$
• B. $T/4$
• C. $T/3$
• D. $T/2$

Answer 1

Answer: (A)

$T/6$

Answer 2

Because the S.H.M. starts from extreme position so $y = a\cos\omega t$ form of S.H.M. should be used.

$\frac{A}{2} = A\cos\frac{2\pi}{T}t$ ⇒$\cos\frac{\pi}{3} = \cos\frac{2\pi}{T}t$ ⇒ $t = T/6$