Question

A simple harmonic oscillator has amplitude 'A' angular frequency ω and mass m. Then average kinetic energy in one time period is –

• A. $\frac{1}{2}$mω²A²
• B. $\frac{1}{4}$mω²A²
• C. mω²A²
• D. Zero

Answer 1

Answer: (B)

$\frac{1}{4}$mω²A²

Answer 2

K_av = $\frac{1}{T}$ $\int_{6}^{T}{\frac{1}{2}m\omega^{2}A^{2}\cos^{2}}$ (ωt + φ)