Question

A simple harmonic oscillator has a period T and energy E. The amplitude of the oscillator is doubled. Choose the correct answer.

• A. Period and energy get doubled.
• B. Period gets doubled while energy remains the same
• C. Energy gets doubled while period remains the same.
• D. Period remains the same and energy becomes four times.

Answer 1

Answer: (D)

Period remains the same and energy becomes four times.

Answer 2

The period of harmonic oscillator does not depend on the amplitude of oscillation.

Energy of oscillator, $E = \frac{1}{2}m\omega^{2}A^{2}$

$E \propto A^{2}$

So, if amplitude (1) is doubled its energy becomes 4 times.