Question

A simple harmonic oscillator has a period of 0.01 sec and an amplitude of 0.2 m. The magnitude of the velocity in $m\sec^{- 1}{}$ at the centre of oscillation is

• A. $20\pi$
• B. 100
• C. 40π
• D. $100\pi$

Answer 1

Answer: (C)

40π

Answer 2

At centre $v_{\text{max}} = a\omega = a.\frac{2\pi}{T} = \frac{0.2 \times 2\pi}{0.01} = 40\pi$