Question

A simple harmonic motion has an amplitude A & time period T. The time required by it to travel from x =A to x = A/2 is –

• A. T/6
• B. T/4
• C. T/3
• D. T/2

Answer 1

Answer: (A)

T/6

Answer 2

Time required to travel from x = A to x = 0 is T/4 & time required to travel from x = A/2 to x = 0 is equal to the time required to travel from x = 0 tot x = A/2 which is equal to

y = A sin (2π/T)tA/2 = A sin (2π/T)t⇒ sin (π/6) = sin (2π/T)t⇒ t = T/12.⇒ Time required to travel from x = A to x A/2 will be T/4 – T/12 = T/6

Hence Answer is (1)