Question

A simple harmonic motion has amplitude A and Time period T. The maximum velocity will be

• A. 4AT
• B. $\frac{2A}{T}$
• C. $2\pi\sqrt{A/T}$
• D. $2\pi\,A/T$

Answer 1

Answer: (D)

$2\pi\,A/T$

Answer 2

As we know $\frac{2 \pi}{\omega}= T$ $\Longrightarrow \omega=\frac{2 \pi}{\pi} T$ Maximum velocity $= A \omega$ $= a \left(\frac{2 \pi}{ T }\right)$