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Question

Physics Question on Current electricity

A silver wire has a resistance of 2.1 Ω at 27.5 °C, and a resistance of 2.7 Ω at 100 °C. Determine the temperature coefficient of resistivity of silver.

Answer

Temperature, T1=27.5°CT_1 = 27.5 °C
Resistance of the silver wire at T1,R1=2.1T_1, R_1 = 2.1 Ω
Temperature, T2=100°CT_2 = 100°C
Resistance of the silver wire at T2,R2=2.7T_2, R_2 = 2.7 Ω
Temperature coefficient of silver = α
It is related with temperature and resistance as
α=R2R1R1(T2T1)α = \frac{R_2-R_1}{R_1(T_2-T_1)}
α=2.72.12.1(10027.5)α = \frac{2.7-2.1}{2.1(100-27.5)}
α=0.0039°C1α = 0.0039 °C^{-1}
Therefore, the temperature coefficient of silver is 0.0039°C1.0.0039 °C^{−1}.