Question

A silver and zinc voltameter are connected in series and a current i is passed through them for a time t liberating W gm of zinc. The weight of silver deposited is nearly

• A. W
• B. 1.7 W
• C. 2.4 W
• D. 3.5 W

Answer 1

Answer: (D)

3.5 W

Answer 2

$\frac{m_{Zn}}{m_{Ag}} = \frac{E_{Zn}}{E_{Ag}}$ ⇒ $m_{Ag} = W\left( \frac{E_{Ag}}{E_{Zn}} \right)$= 3.3 W = 3.5 W