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Question

Chemistry Question on Some basic concepts of chemistry

A signature written with carbon pencil weighs 1 mg. What is the number of carbon atoms present in the signature ?

A

6.02×10206.02 \times 10^{20}

B

0.502×10200.502 \times 10^{20}

C

5.02×10235.02 \times 10^{23}

D

5.02×10205.02 \times 10^{20}

Answer

0.502×10200.502 \times 10^{20}

Explanation

Solution

12 gm12 \, \text{gm} carbon contain = 6.023×10236.023 \times 10^{23}
(10)−23 gm(1mg)=6.023×(10)2312×(10)−3\left(10\right)^{- 23} \, \text{gm} \left(\text{1mg}\right) = \frac{6.023 \times \left(10\right)^{23}}{12} \times \left(10\right)^{- 3}
=0.502×1020= 0.502 \times 10^{20}