Question

A short electric dipole has a dipole moment of $16 \times 10^{-9} C\, m$. The electric potential due to the dipole at a point at a distance of $0.6 \,m$ from the centre of the dipole, situated on a line making an angle of $60\degree$with the dipole axis is : $(\frac {1}{4\pi \epsilon_o}= 9 \times 10^9 N\,m^2/C^2)$

• A. $50\,V$
• B. $200\,V$
• C. $400\,V$
• D. zero

Answer 1

Answer: (B)

$200\,V$

Answer 2

The correct answer is B:$200V$
The electric potential due to the dipole,
$V=\frac{kp\,cos\,theta}{r^{2}}$
Here: $K=\frac{1}{4\pi \in_0}=9\times10^9Nm^2/C^2$
$r=0.6m$
$P=16\times 10^{-9}Cm$
Putting these values in the formula we get;
$V=\frac{9\times 10^{9}\times 16\times 10^{-9}}{(0.6)^{2}}\times \frac{1}{2}$
$V=200\,V$