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Question

Physics Question on Electromagnetic induction

A short- circuited coil is placed in a time varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to be quadrupled (four times) and wire radius halved, the electrical power dissipated would be

A

halved

B

the same

C

doubled

D

quadrupled

Answer

the same

Explanation

Solution

P=ε2RP =\frac{\varepsilon^{2}}{ R } where, ε=\varepsilon= inducedemf =dϕdt=-\frac{ d \phi}{ d t} ϕ=NBA\phi= N B A ε=NAddt\varepsilon= N A \frac{ d }{ d t} also, R1r2R \propto \frac{1}{ r ^{2}} where, R=R= resistance and r=r= radius of wire PN2r212P \propto \frac{ N ^{2} r ^{2}}{1^{2}} P1P2=1\frac{ P _{1}}{ P _{2}}= 1 P1=P2P _{1}= P _{2} This means if the number of turns were quadrupled and the wire radius halved, the electrical power dissipated would be remains same.