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Question: A shopkeeper professes to sell his goods at cost price but uses a weight of \[800\] grams instead of...

A shopkeeper professes to sell his goods at cost price but uses a weight of 800800 grams instead of a kilogram weight. Thus, he makes a gain of:
A. 10%10\%
B. 15%15\%
C. 20%20\%
D. 25%25\%

Explanation

Solution

Here we will be using the formula of gain percentage i.e. Gain%=GainOriginal weight×100{\text{Gain}}\% = \dfrac{{{\text{Gain}}}}{{{\text{Original weight}}}} \times 100 , where the gain is the difference between the original weight and the new weight.

Complete answer:
Step 1: As we know that one kilogram equals
10001000 grams. The actual weight used by the shopkeeper is
800800 grams so we will be calculating the gain by subtracting the original weight from the new/actual weight as shown below:
Gain = 1000 - 800{\text{Gain = 1000 - 800}}
By doing the subtraction in the RHS side of the above expression we get:
Gain = 200\Rightarrow {\text{Gain = 200}}
Step 2: We will be using the formula Gain%=GainOriginal weight×100{\text{Gain}}\% = \dfrac{{{\text{Gain}}}}{{{\text{Original weight}}}} \times 100 to calculate the gain percentage by substituting the values of
Gain = 200{\text{Gain = 200}} and
Original weight = 800{\text{Original weight = 800}} as calculated below:
Gain%=200800×100\Rightarrow {\text{Gain}}\% = \dfrac{{200}}{{800}} \times 100
By solving the division in the RHS side of the above expression we get:
Gain%=1004\Rightarrow {\text{Gain}}\% = \dfrac{{100}}{4}
By doing the final division in the above expression we get:
Gain%=25%\Rightarrow {\text{Gain}}\% = 25\%

Option D is correct.

Note:
Students need to take care while solving these types of questions that the amount of discount which is given on the marked price equals to as below:
Discount %100×M.P\dfrac{{{\text{Discount }}\% }}{{100}} \times {\text{M}}{\text{.P}}, and we will be subtracting this value from the marked price for calculating the value of the selling price.
Also, you should remember which one is the original weight and which one is new for calculating the value of gain.